# Bosch Esi Tronic C Kw Archive Discs 03 2012 Torrent

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Q:

Is a decrease in $\text{Vss}$ of a transistor’s drive current of a very large value possible?

Let’s suppose we have a transistor which can drive a LED from a source of 5V which is not its source of operation, but an alternative one. This transistor is designed for some applications. There is a reference which shows the characteristics of such a transistor. Let the drive current be 1 mA and consider the \$V_{\text{CE}} \$ is 0.9V. Since the decrease in the drive current by this value is small, so let’s assume it has remained unaffected. If the \$V_{\text{CC}} \$ is decreased by 300mV(by parallel arrangement with two resistors), is it possible that the \$V_{\text{CE}} \$ decreases by 300mV? Would this not destroy the operation of the transistor?

A:

If the VCE is perfectly sensitive enough, a change of 300 mV in voltage VCC will lower the current flowing through the base enough to cause the transistor to turn off. But in reality you cannot guarantee that it will be perfect and you are right that for the transistor to function properly, a change in VCC should not make the collector current lower than the required base current.
The reason why your transistor won’t work is that when you put some other voltage source at the base instead of the 5V pin, this other voltage source might have different characteristics or an impedance between the base and the emitter which might make the transistor turn off.

A:

If you put another source of current into base, that will affect the VCE to the point that you will get no or only a very little current at the base. So yes, 300 mV is possible.
I would just try it in the breadboard and see what happens. Most likely you will get no current at the base, but if the emitter is not connected to the power pin, what is there now is useless.

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